Solve the following systems of linear in equations:

, x > 0


and


When,



Subtracting 3 from both the sides






Signs of 1 – 3x:


1 – 3x = 0


(Subtract 1 from both the sides and then divide both sides by -3)


1 – 3x > 0


(Subtract 1 from both the sides, then multiply by -1 on both sides and then divide both sides by 3)


1 – 3x < 0


(Subtract 1 from both the sides, then multiply by -1 on both sides and then divide both sides by 3)


Interval satisfying the required condition ≤ 0 , x > 0


or


Or



Now when,



Subtracting 3 from both the sides






Dividing both sides by 3



Multiplying by -1 on both sides



Signs of x - 1:


x – 1 = 0 x = 1 (Adding 1 to both the sides)


x – 1 > 0 x > 1 (Adding 1 to both the sides)


x – 1 < 0 x < 1 (Adding 1 to both the sides)


Interval satisfying the required condition: ≤ 0


x ≤ 1


Combining the intervals:


such that x > 0


1