-11 ≤ 4x – 3 and 4x – 3 ≤ 13

When,

-11 ≤ 4x - 3

4x – 3 ≥ -11

Adding 3 to both the sides

4x – 3 + 3 ≥ -11 + 3

4x ≥ - 8

Divide both the sides by 4 in above equation

x ≥ -2

Now when,

4x – 3 ≤ 13

Adding 3 to both the sides in the above equation

4x – 3 + 3 ≤ 13 + 3

4x ≤ 16

Dividing both the sides by 4 in the above question

x ≤ 4

Combining the intervals:
x ≥ -2 and x ≤ 4

Therefore,

x ϵ [-2, 4]