Solve the following systems of linear in equations:

5x – 7 < (x + 3), 1 –x – 4


When,


5x – 7 < x + 3


Adding 7 to both the sides in the above equation


5x – 7 + 7 < x + 3 + 7


5x < x + 10


Now, subtracting x from both the sides


5x – x < x + 10 -x


4x < 10


Dividing both the sides by 4 in above equation




Now when,


1 – ≥ x – 4


Subtracting 1 from both the sides in the above equation


1 - -1 ≥ x – 4 – 1


≥ x - 5


Now multiplying both the sides by 2 in the above equation


≥ 2x – 10


-3x ≥ 2x – 10


Now subtracting 2x from both the sides in the above equation


-3x – 2x ≥ 2x -10 – 2x


-5x ≥ -10


Now, multiplying both the sides by -1 in the above equation


-5x(-1) ≥ -10(-1)


5x ≤ 10


Now, dividing both the sides by 5 in the above equation



x ≤ 2


Therefore,


and x ≤ 2


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