Solve the following systems of linear in equations:
5x – 7 < (x + 3), 1 –x – 4
When,
5x – 7 < x + 3
Adding 7 to both the sides in the above equation
5x – 7 + 7 < x + 3 + 7
5x < x + 10
Now, subtracting x from both the sides
5x – x < x + 10 -x
4x < 10
Dividing both the sides by 4 in above equation
Now when,
1 – ≥ x – 4
Subtracting 1 from both the sides in the above equation
1 - -1 ≥ x – 4 – 1
≥ x - 5
Now multiplying both the sides by 2 in the above equation
≥ 2x – 10
-3x ≥ 2x – 10
Now subtracting 2x from both the sides in the above equation
-3x – 2x ≥ 2x -10 – 2x
-5x ≥ -10
Now, multiplying both the sides by -1 in the above equation
-5x(-1) ≥ -10(-1)
5x ≤ 10
Now, dividing both the sides by 5 in the above equation
x ≤ 2
Therefore,
and x ≤ 2