Solve the following systems of linear in equations:

3x – x > x + > 3


3x – x > x + and x + > 3


When,


3x – x > x +


2x > x +


Subtracting x from both the sides in above equation


2x – x > x + - x


x >


Multiplying both the sides by 3 in the above equation


3x > 3


3x > 4 – x


Adding x on both the sides in above equation


3x + x > 4 -x + x


4x > 4


Dividing both the sides by 4 in above equation



x > 1


Now when,


x + > 3


Multiplying both the sides by 3 in above equation


3x + 3 > 3(3)


3x + 4 – x > 9


2x + 4 > 9


Subtracting 4 from both the sides in above equation


2x + 4 – 4 > 9 – 4


2x > 5


Dividing both the sides by 2 in above equation


>



Merging overlapping intervals



Therefore,



1