Solve the following systems of linear in equations:

+ 11 < 0


When,



Multiplying both the sides by 2



7x -1 < -6


Adding 6 to both the sides in above equation


7x – 1 + 6 < -6 + 6


7x + 5 < 0


Subtracting 5 from both the sides in above equation


7x + 5 – 5 < 0 – 5


7x < - 5


Dividing both the sides by 7 in above equation



Therefore,



Now when,


+ 11 < 0


Subtracting both the sides by 11 in the above equation


+ 11 -11 < 0 – 11


< -11


Multiplying both the sides by 5 in the above equation


(5) < -11(5)


3x + 8 < -55


Subtracting 8 from both the sides in above equation


3x + 8 – 8 < -55 – 8


3x < -63


Dividing both the sides by 3 in above equation



Therefore,


x < -21


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