Solve the following systems of linear in equations:
+ 11 < 0
When,
Multiplying both the sides by 2
7x -1 < -6
Adding 6 to both the sides in above equation
7x – 1 + 6 < -6 + 6
7x + 5 < 0
Subtracting 5 from both the sides in above equation
7x + 5 – 5 < 0 – 5
7x < - 5
Dividing both the sides by 7 in above equation
Therefore,
Now when,
+ 11 < 0
Subtracting both the sides by 11 in the above equation
+ 11 -11 < 0 – 11
< -11
Multiplying both the sides by 5 in the above equation
(5) < -11(5)
3x + 8 < -55
Subtracting 8 from both the sides in above equation
3x + 8 – 8 < -55 – 8
3x < -63
Dividing both the sides by 3 in above equation
Therefore,
x < -21