Solve the following systems of linear in equations:

–12 < 4 – ≤ 2


-12 < 4 – and 4 – ≤ 2


When,


-12 < 4 –


4 – > -12


Subtracting 4 from both the sides in above equation


4 -4 > 12 – 4


> -16


> -16


Multiplying both the sides by 5 in the above equation


> -16(5)


3x > -80


Dividing both the sides by 3 in above equation


>


Therefore,


x >


Now when,


4 – ≤ 2


Subtracting both the sides by 4 in the above equation


4 – – 4 ≤ 2 – 4


≤ - 2


≤ -2


Multiplying both the sides by 5 in the above equation


3x ≤ -10


Dividing both the sides by 3 in the above equation



Therefore,



Therefore:


1