To find: number of arrangements of 5 people in 3 seats.

Consider three seats A B C

Now, place A can be occupied by any 1 person out of 5.

Then place B can be occupied by any 1 person from remaining 4 and for C there are 3 people to occupy the seat.

Formula:

Number of permutations of n distinct objects among r different places, where repetition is not allowed, is

P(n,r) = n!/(n-r)!

Therefore, permutation of 5 different objects in 3 places is

P(5,3) =

= = = 60.

Therefore, the number of possible solutions is 60.