How many 6 - digit numbers can be formed by using the digits 4, 5, 0, 3, 4, 5?

To find: number of 6 digit


0 cannot be in the first place because that would make a 5 - digit number


Total number of 6 - digit numbers = Total number of number possible - Number of numbers with 0 at the first place


Total number of numbers possible =


Number of numbers with 0 at first place =


Number of 6 - digit numbers = 180 - 30 = 150


150 six - digit numbers are possible


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