Using binomial theorem, expand each of the following:
To find: Expansion of
Formula used: (i)
(ii) (a+b)n = nC0an + nC1an-1b + nC2an-2b2 + …… +nCn-1abn-1 + nCnbn
We have,
⇒ 5C0(x)5-0 + 5C1(x)5-1 + 5C2(x)5-2
+ 5C3(x)5-3
+ 5C4(x)5-4
+ 5C5
⇒
Ans)