Find the coefficient of x4 in the expansion of (1 + x)n (1 – x)n. Deduce that C2 = C0C4 – C1C3 + C2C2 – C3C1 + C4C0, where Cr stands for nCr.
To Find : Coefficients of x4
For (1+x)n
a=1, b=x
We have a formula,
For (1-x)n
a=1, b=-x and n=n
We have formula,
Coefficients of x4 are
x0.x4 = C0C4
x1.x3 = - C1C3
x2.x2 = C2C2
x3.x1= - C3C1
x4.x0 = C4C0
Therefore, Coefficient of x4
= C4C0 - C1C3 + C2C2 - C3C1 + C4C0
Let us assume, n=4, it becomes
4C4 4C0 - 4C1 4C3 + 4C2 4C2 - 4C3 4C1 + 4C4 4C0
We know that ,
By using above formula, we get,
4C4 4C0 - 4C1 4C3 + 4C2 4C2 - 4C3 4C1 + 4C4 4C0
= (1)(1) – (4)(4) + (6)(6) – (4)(4) + (1)(1)
= 1 – 16 + 36 – 16 + 1
= 6
= 4C2
Therefore, in general,
C4C0 - C1C3 + C2C2 - C3C1 + C4C0 = C2
Therefore, Coefficient of x4 = C2
Conclusion :
• Coefficient of x4 = C2
• C4C0 - C1C3 + C2C2 - C3C1 + C4C0 = C2