Find the 20th term of the AP , 3, 5, 7 , ….

To Find: 20th term of the AP


Given: The series is √2, 3√2, 5√2, 7√2, ….


a1=√2, a2= 3√2 and d= 3√2–√2= 2√2


(Where a=a1 is first term, a2 is second term, an is nth term and d is common difference of given AP)


Formula Used: an = a + (n - 1)d


a20= a1 + (20 - 1)( 2√2)= √2 + 38√2= 39√2


So 20rd term of AP is equal to 39√2.


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