Which term of the AP 64, 60, 56, 52, 48, …. is 0?

To Find: we need to find n when an = 0


Given: The series is 64, 60, 56, 52, 48, … and an= 0


a1=64, a2= 60 and d=60–64 = –4


(Where a=a1 is first term, a2 is second term, an is nth term and d is common difference of given AP)


Formula Used: an = a + (n - 1)d


an= 0 = a1 + (n–1)(–4)


0– 64 = (n–1)(–4) [subtract 64 on both sides]


– 64 = (n–1)(–4)


64 = (n–1)4 [Divide both side by ‘–‘]


16 = (n–1) [Divide both side by 4]


n = 17th [add 1 on both sides]


The 17th term of this AP is equal to 0.


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