Which term of the AP 64, 60, 56, 52, 48, …. is 0?
To Find: we need to find n when an = 0
Given: The series is 64, 60, 56, 52, 48, … and an= 0
a1=64, a2= 60 and d=60–64 = –4
(Where a=a1 is first term, a2 is second term, an is nth term and d is common difference of given AP)
Formula Used: an = a + (n - 1)d
an= 0 = a1 + (n–1)(–4)
0– 64 = (n–1)(–4) [subtract 64 on both sides]
– 64 = (n–1)(–4)
64 = (n–1)4 [Divide both side by ‘–‘]
16 = (n–1) [Divide both side by 4]
n = 17th [add 1 on both sides]
The 17th term of this AP is equal to 0.