How many terms are there in the AP 11, 18, 25, 32, 39, …. 207?

To Find: we need to find a number of terms in the given AP.


Given: The series is 11, 18, 25, 32, 39, …. 207


a1=11, a2= 18,d=18–11 = 7 and an=207


(Where a=a1 is first term, a2 is second term, an is nth term and d is common difference of given AP)


Formula Used: an = a + (n–1)d


an= 207 = a1 + (n–1)(7)


207– 11 = (n–1)(7) [subtract 11 on both sides]


196 = (n–1)(7)


28 = (n–1) [Divide both side by 7]


n = 29 [add 1 on both sides]


So there are 29 terms in this AP.


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