How many terms are there in the AP 11, 18, 25, 32, 39, …. 207?
To Find: we need to find a number of terms in the given AP.
Given: The series is 11, 18, 25, 32, 39, …. 207
a1=11, a2= 18,d=18–11 = 7 and an=207
(Where a=a1 is first term, a2 is second term, an is nth term and d is common difference of given AP)
Formula Used: an = a + (n–1)d
an= 207 = a1 + (n–1)(7)
207– 11 = (n–1)(7) [subtract 11 on both sides]
196 = (n–1)(7)
28 = (n–1) [Divide both side by 7]
n = 29 [add 1 on both sides]
So there are 29 terms in this AP.