The 4th term of an AP is three times the first and the 7th term exceeds twice the third term by 1. Find the first term and the common difference.

To Find: First term (a) and common difference (d)


Given: a4= 3a1 and a7 = 2a3 + 1


(Where a=a1 is first term, an is nth term and d is common difference of given AP)


Formula Used: an = a + (n - 1)d


a4= 3a1 a + 3d= 3a 3d = 2a ….equation (i) and


a7 = 2a3 + 1 a + 6d= 2(a + 2d) + 1 2d= a + 1 ….equation (ii)


on solving both equation (i) & (ii), we get


a= 3 and d= 2


So the first term is equal to 3, and the common difference is equal to 2.


1