Find the 16th term from the end of the AP 7, 2, –3, –8, –13, …., –113

To Find : 28th term from the end of the AP.


Given: The AP is 7, 2, –3, –8, –13, …., –113


a1 = 7, a2 = 2, d = 2–7 = –5 and l = –113


Formula Used: nth term from the end = l– (n–1)d


(Where lis last term and d is common difference of given AP)


By using nth term from the end = l– (n–1)d formula


16th term from the end = (–113)– 15d (–113)–15(–5) = –38


So 16th term from the end is equal to –38.


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