A man starts repaying a loan as the first instalment of 10000. If he increases the instalment by 500 every month, what amount will he pay in 30th instalment?

To Find: what amount will he pay in the 30th instalment.


Given: first instalment =10000 and it increases the instalment by 500 every month.


So it form an AP with first term is 10000, common difference 500 and number of instalment is 30


Formula Used: Tn = a + (n - 1)d


(Where a is first term, Tn is nth term and d is common difference of given AP)


Tn = a + (n - 1)d Tn = 10000 + (30 - 1)500 Tn = 10000 + 29500


Tn = 10000 + 14500 Tn = 24,500


So, he will pay 24,500 in the 30th instalment.


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