If the sum of a certain number of terms of the AP 27, 24, 21, 18, …. is –30, find the last term.
To Find: Last term of the AP.
Let the number of terms be n.
⇒n[54 - 3n + 3] = - 60
⇒3n2 - 57n - 60 = 0
Either n = 20 or n = - 1 (n cannot be negative)
Therefore n = 20
Also,
, where l is the last term.
⇒ - 30 = 270 + 10l
⇒l = - 30
The last term is - 30.