A man saved ₹660000 in 20 years. In each succeeding year after the first year, he saved ₹2000 more than what he saved in the previous year. How much did he save in the first year?

Given: -


Amount saved by a man in 20 years is Rs.660000.


Let the amount saved by him in the first year be.


In every succeeding year, he saves Rs.2000 more than what he saved in the previous year.


Increment of saving of the year when compared last year is Rs.2000


Hint: - The above information looks like the savings are in Arithmetic Progression.


Amount saved in first year = a


Common difference = d = ₹2000


Total number of years = n = 20


The total amount saved in 20 years is ₹660000


Sum of n terms in an A.P



a = 14000


In the first year, he saved ₹14000.


1