The 9th term of an AP is 0. Prove that its 29th term is double the 19th term.
Given :9th term is 0
To prove: 29th term is double the 19th term
a + 8d = 0
a = - 8d
29th term is
a + 28d
⟹ 20d
19th term is
a + 18d
⟹ 10d
Hence proved 29th term is double the 19th term