Given GP is √3, 3, 3√3….

The given GP is of the form, a, ar, ar², ar³….

Where r is the common ratio.

First term in the given GP, a₁ = a = √3

Second term in GP, a₂ = 3

Now, the common ratio,

Let us consider 729 as the n^th term of the GP.

Now, n^th term of GP is, a_n = ar^{n – 1}

729 = √3 (√3) ^{n – 1}

√3ⁿ = √3¹²

n = 12

So, 729 is the 12^th term in GP.