The given GP is 8, 4, 2….→ (1)

First term in the GP, a₁ = a = 8

Second term in the GP, a₂ = ar = 4

The common ratio,

The last term in the given GP is.

Second last term in the GP = a_n-1 = ar^n-2

Starting from the end, the series forms another GP in the form,

ar^n-1, ar^n-2, ar^n-3….ar³, ar², ar, a → (2)

Common ratio of this GP is .

So, common ratio = 2

So, 6^th term of the GP (2),

a₆ = ar⁵

=

Hence, the 6^th term from the end of the given GP is.