The common ratio of a finite GP is 3, and its last term is 486. If the sum of these terms is 728, find the first term.

‘Tn’ represents the nth term of a G.P. series.


Tn = arn-1


486 = a(3)n-1


486 = a( 3n ÷ 3) )


486 × 3 = a(3n)


1458 = a(3n ) ………(i)


Sum of a G.P. series is represented by the formula, , when r≠1. ‘Sn’ represents the sum of the G.P. series upto nth terms, ‘a’ represents the first term, ‘r’ represents the common ratio and ‘n’ represents the number of terms.




728 × 2 = a (3n)-a …… [ Putting a(3n ) = 1458 fromk (i) ]


1456 = 1458 -a


1456-1458 = -a


-2=-a [ Multipying both sides by -1]


a = 2


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