If (p2 + q2), (pq + qr), (q2 + r2) are in GP then prove that p, q, r are in GP
To prove: p, q, r are in GP
Given: (p2 + q2), (pq + qr), (q2 + r2) are in GP
Formula used: When a,b,c are in GP, b2 = ac
Proof: When (p2 + q2), (pq + qr), (q2 + r2) are in GP,
(pq + qr)2 = (p2 + q2) (q2 + r2)
p2q2 + 2pq2r + q2r2 = p2q2 + p2r2 + q4 + q2r2
2pq2r = p2r2 + q4
pq2r + pq2r = p2r2 + q4
pq2r - q4 = p2r2 - pq2r
q2(pr – q2) = pr (pr – q2)
q2 = pr
From the above equation we can say that p, q and r are in G.P.