If , find the value of .

It is given that,


Note:


I. Sum of first n natural numbers, 1 + 2 +3+…n,



II. Sum of squares of first n natural numbers, 12 + 22 + 32+….n2,



From the above identities,



n2 + n = 420


n2 + n -420 = 0


(n – 20) (n + 21) = 0


n = 20 or -21


Since, n is the number of integers, n = 20



So,


1