Given: sin x = and <x< i.e, x lies in the Quadrant II .

To Find: i)sin ii)cos iii)tan

Now, since sin x =

We know that cos x =

cos x =

cos x =

cos x =

since cos x is negative in II quadrant, hence cos x = -

i) sin

Formula used:

sin =

Now, sin = = =

Since sinx is positive in II quadrant, hence sin

ii)cos

Formula used:

cos =

now, cos = = = = =

since cosx is negative in II quadrant, hence cos =

iii)tan

Formula used:

tan x =

hence, tan = = = = -

Here, tanx is negative in II quadrant.