In any ΔABC, prove that
2(bc cos A + ca cos B + ab cos C) = (a2 + b2 + c2)
Need to prove: 2(bc cos A + ca cos B + ab cos C) = (a2 + b2 + c2)
Left hand side
2(bc cos A + ca cos B + ab cos C)
b2 + c2 – a2 + c2 + a2 – b2 + a2 + b2 – c2
a2 + b2 + c2
Right hand side. [Proved]