Given: The vertices of the triangle are A(-3, -5), B(5, 2) and C(-9, -3).

Formula: Area of Δ ABC

Here,

x₁ = -3, y₁ = -5

x₂ = 5, y₂ = 2

x₃ = -9, y₃ = -3

Putting the values,

Area of Δ ABC

= 29 square units.

Therefore, the area of Δ ABC is 29 square units.