Find the equation of the line whose

(i) slope = 3 and y - intercept = 5


(ii) slope = - 1 and y - intercept = 4


(iii) slope = and y - intercept = - 3


(i) Formula to be used: y = mx + c where m is the slope of the line and c is the y - intercept.


Here, m = 3 and c = 5.


Hence, y = (3)x + (5)


i.e. y = 3x + 5


(ii) Formula to be used: y = mx + c where m is the slope of the line and c is the y - intercept.


Here, m = - 1 and c = 4.


Hence, y = ( - 1)x + (4)


i.e. x + y = 4


(iii) Formula to be used: y = mx + c where m is the slope of the line and c is the y - intercept.


Here, m = and c = - 3.


Hence, y = ()x + ( - 3)


Or, 5y = - 2x - 3 i.e. 2x + 5y + 3 = 0


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