Find the equation of the line whose
(i) slope = 3 and y - intercept = 5
(ii) slope = - 1 and y - intercept = 4
(iii) slope = and y - intercept = - 3
(i) Formula to be used: y = mx + c where m is the slope of the line and c is the y - intercept.
Here, m = 3 and c = 5.
Hence, y = (3)x + (5)
i.e. y = 3x + 5
(ii) Formula to be used: y = mx + c where m is the slope of the line and c is the y - intercept.
Here, m = - 1 and c = 4.
Hence, y = ( - 1)x + (4)
i.e. x + y = 4
(iii) Formula to be used: y = mx + c where m is the slope of the line and c is the y - intercept.
Here, m = and c = - 3.
Hence, y = ()x + ( - 3)
Or, 5y = - 2x - 3 i.e. 2x + 5y + 3 = 0