Find the equation of the line which is parallel to the line 2x – 3y = 8 and whose y - intercept is 5 units.
Given: The given line is 2x - 3y = 8. The line parallel to this line has a y - intercept of 5units.
Formula to be used: If ax + by = c is a straight line then the line parallel to the given line is of the form ax + by = d, where a,b,c,d are arbitrary real constants.
A line parallel to the given line has a slope of and is of the form 2x - 3y = k , where k is any arbitrary real constant.
Now, 2x - 3y = k
or, 3y = 2x - k
which is of the form y = mx + c , where c is the y - intercept.
So, k = ( - 3)x5 = - 15
Equation of the required line is 2x - 3y = - 15
i.e. 2x - 3y + 15 = 0