Find the equation of the line passing through the point (0, 3) and perpendicular to the line x – 2y + 5 = 0
Given: The given line is x - 2y + 5 = 0. The line perpendicular to this given line passes through (0,3)
Formula to be used: The product of slopes of two perpendicular lines = - 1.
The slope of this line is 1/2 .
the slope of the perpendicular line =
The equation of the line can be written in the form y = ( - 2)x + c
(c is the y - intercept)
This line passes through (0,3) so the point will satisfy the equation of the line.
3 = ( - 2)x0 + c i.e. c = 3
The required equation is y = - 2x + 3
i.e. 2x + y = 3