Given: Point (3,-5) and line 3x – 4y = 27

To find: The distance of the point (3, -5) from the line 3x – 4y = 27

Formula used:

We know that the distance between a point P(m,n) and a line ax + by + c = 0 is given by,

D

The equation of the line is 3x – 4y - 27=0

Here m= 3 and n = -5 , a = 3 , b = -4 , c = -27

D

D

D

The distance of the point (3, -5) from the line 3x – 4y = 27 is units