A vertex of a square is at the origin and its one side lies along the line 3x – 4y – 10 = 0.
Find the area of the square.
Given: ABCD is a square and equation of BC is 3x – 4y – 10 = 0
To find : Area of the square
Formula used:
We know that the length of perpendicular from (m,n) to the line ax + by + c = 0 is given by,
D
The given equation of the line is 3x – 4y – 10 = 0
Here m= 0 and n= 0 , a = 3 , b = -4 , c = -10
D
D
D
Side of the square=D=2
Area of the square = 22 = 4 square units
Area of the square = 4 square units