Find the distance between the parallel lines 4x – 3y + 5 = 0 and 4x – 3y + 7 = 0

Given: parallel lines 4x – 3y + 5 = 0 and 4x – 3y + 7 = 0


To find : distance between the parallel lines


Formula used :


The distance between the parallel lines ax + by + c =0 and ax + by + d =0 is,


D



Here a = 4 ,b = -3 ,c = 5 ,d = 7


D


The distance between the parallel lines 4x – 3y + 5 = 0 and 4x – 3y + 7 = 0 is units


1