Find the distance between the parallel lines p(x + y) = q = 0 and p(x + y) – r =0

Given: parallel lines p(x + y) = q = 0 and p(x + y) – r =0


To find : distance between the parallel lines p(x + y) - q = 0 and p(x + y) – r =0


Formula used :


The distance between the parallel lines ax + by + c =0 and ax + by + d =0 is,


D



The parallel lines are p(x + y) - q = 0 and p(x + y) – r =0


The parallel lines are px + py - q = 0 and px + py – r = 0


Here a = p ,b = p ,c = -q ,d = -r


D


The distance between the parallel lines p(x + y) =q = 0 and p(x + y) – r = 0 is units


1