Prove that the line 12x – 5y – 3 = 0 is mid-parallel to the lines 12x – 5y + 7 = 0 and 12x – 5y – 13 = 0
Given: parallel lines 12x – 5y – 3 = 0, 12x – 5y + 7 = 0, 12x – 5y – 13 = 0
To Prove : line 12x – 5y – 3 = 0 is mid-parallel to the lines 12x – 5y + 7 = 0 and 12x – 5y – 13 = 0
Formula used :
The distance between the parallel lines ax + by + c =0 and ax + by + d =0 is,
D
The equation of line l is 12x – 5y + 7 = 0
The equation of line m is 12x – 5y – 3 = 0
The equation of line n is 12x – 5y – 13 = 0
Let D1 be the distance between the lines l and m .
Here a = 12 ,b = -5 ,c = 7 ,d = -3
The distance between the parallel lines l and m is units
Let D2 be the distance between the lines m and n .
Here a = 12 ,b = -5 ,c = 7 ,d = -3
D2
The distance between the parallel lines m and n is units
Distance between the parallel lines l and m = Distance between the parallel lines m and n
Thus the line 12x – 5y – 3 = 0 is mid-parallel to the lines 12x – 5y + 7 = 0 and 12x – 5y – 13 = 0