Find the mean deviation about the median for the following data :
class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 |
Frequency | 6 | 8 | 11 | 18 | 5 | 2 |
we make the following table from the given data:
class | Frequency fi | Cumulative frequency c.f | Mid-points xi |
0-10 | 6 | 6 | 5 |
10-20 | 8 | 14 | 15 |
20-30 | 11 | 25 | 25 |
30-40 | 18 | 43 | 35 |
40-50 | 5 | 48 | 45 |
50-60 | 2 | 50 | 55 |
50 |
The class interval containing or 25th item is 20-30. Therefore, 20–30 is the median class. We know that
Here, l = 20, C = 14, f = 11, h = 10 and N = 50
Therefore,
Now,
class | Frequency fi | Cumulative frequency c.f | Mid-points xi | |xi-M| | fi |xi-M| |
0-10 | 6 | 6 | 5 | 25 | 150 |
10-20 | 8 | 14 | 15 | 15 | 120 |
20-30 | 11 | 25 | 25 | 5 | 55 |
30-40 | 18 | 43 | 35 | 5 | 90 |
40-50 | 5 | 48 | 45 | 15 | 75 |
50-60 | 2 | 50 | 55 | 25 | 50 |
50 | 540 |
We have, and