If the standard deviation of the numbers 2, 3, 2x, 11 is 3.5, calculate the possible values of x.

Given: Standard Deviation, σ = 3.5

and Numbers are 2, 3, 2x, 11


We know that,










12.25 × 16 = 280 – 64x + 12x2


196 = 280 – 64x + 12x2


12x2 – 64x + 280 – 196 = 0


12x2 – 64x + 84 = 0


3x2 – 16x + 21 = 0


3x2 – 9x – 7x + 21 = 0


3x(x – 3) – 7(x – 3) = 0


(3x – 7)(x – 3) = 0


Putting both the factors equal to 0, we get


3x – 7 = 0 and x – 3 = 0


3x = 7 and x = 3




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