The mean and standard deviations of a group of 100 observations were found to be 20 and 3 respectively. Later on it was found that three observations 21, 12 and 18 were incorrect. Find the mean and standard deviation if the incorrect observations were omitted.
Given that number of observations (n) = 100
Incorrect Mean (x̅ ) = 20
and Incorrect Standard deviation, (σ) = 3
We know that,
…(i)
∴ Incorrect sum of observations = 2000
Finding correct sum of observations, incorrect observations 21, 12 and 18 are removed
So, Correct sum of observations = Incorrect Sum – 21 – 12 – 18
= 2000 – 51
= 1949
Hence,
= 20.09
Now, Incorrect Standard Deviation (σ)
Squaring both the sides, we get
Since, 21, 12 and 18 are removed
So,
= 40900 – 441 – 144 – 324
= 40900 – 909
= 39991
Now,
Correct Standard Deviation
= 2.94
Hence, Correct Mean = 20.09
and Correct Standard Deviation = 2.94