The mean and standard deviations of a group of 100 observations were found to be 20 and 3 respectively. Later on it was found that three observations 21, 12 and 18 were incorrect. Find the mean and standard deviation if the incorrect observations were omitted.

Given that number of observations (n) = 100

Incorrect Mean (x̅ ) = 20


and Incorrect Standard deviation, (σ) = 3


We know that,






…(i)


Incorrect sum of observations = 2000


Finding correct sum of observations, incorrect observations 21, 12 and 18 are removed


So, Correct sum of observations = Incorrect Sum – 21 – 12 – 18


= 2000 – 51


= 1949


Hence,





= 20.09


Now, Incorrect Standard Deviation (σ)






Squaring both the sides, we get








Since, 21, 12 and 18 are removed


So,



= 40900 – 441 – 144 – 324


= 40900 – 909


= 39991


Now,


Correct Standard Deviation







= 2.94


Hence, Correct Mean = 20.09


and Correct Standard Deviation = 2.94


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