To find: Differentiation of x² sin x

Formula used: (i) (uv)′ = u′v + uv′ (Leibnitz or product rule)

(ii)

(iii)

Let us take u = x² and v = sinx

Putting the above obtained values in the formula:-

(uv)′ = u′v + uv′

(x² sin x)’ = 2x × sinx + x² × cosx

= 2xsinx + x²cosx

Ans) 2xsinx + x²cosx