Differentiate







(v) (uv)′ = u′v + uv′ (Leibnitz or product rule)


Let us take u = () and v = ()



Applying Product rule


(gh)′ = g′h + gh′


Taking g = ex and h = sinx


= exsinx + excosx


u’ = exsinx + excosx



Putting the above obtained values in the formula:-














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