Differentiate
(iv) (uv)′ = u′v + uv′ (Leibnitz or product rule)
Let us take u = ex(x-1) and v = (x+1)
Applying Product rule
(gh)′ = g′h + gh′
Taking g = and h = x – 1
[ex(x-1)]’ = ex(x-1) + ex (1)
= ex(x-1) + ex
u’ = exx
Putting the above obtained values in the formula:-