Differentiate
(iv) (uv)′ = u′v + uv′ (Leibnitz or product rule)
Let us take u = (x tanx) and v = (secx + tanx)
Applying Product rule for finding u’
(gh)′ = g′h + gh′
Taking g = xand h = tanx
[]’ = (1) (tanx) + x (sec2x)
= tanx + xsec2x
u’ = tanx + xsec2x
Putting the above obtained values in the formula:-