Differentiate
(iv) (uv)′ = u′v + uv′ (Leibnitz or product rule)
Let us take u = () and v = (
)
Applying Product rule for finding the term xcosx in u’
(gh)′ = g′h + gh′
Taking g = xand h = cosx
[]’ = (1) (cosx) + x (-sinx)
[]’ = cosx – x sinx
Applying the above obtained value for finding u’
u’ = cosx – (cosx – x sinx)
u’ = x sinx
Applying Product rule for finding the term xsinx in v’
(gh)′ = g′h + gh′
Taking g = xand h = sinx
[]’ = (1) (sinx) + x (cosx)
[]’ = sinx + x cosx
Applying the above obtained value for finding v’
v’ = sinx + x cosx - sinx
v’ = x cosx
Putting the above obtained values in the formula:-