Differentiate






(iv) (uv)′ = u′v + uv′ (Leibnitz or product rule)


Let us take u = () and v = ()



Applying Product rule for finding the term xcosx in u’


(gh)′ = g′h + gh′


Taking g = xand h = cosx


[]’ = (1) (cosx) + x (-sinx)


[]’ = cosx – x sinx


Applying the above obtained value for finding u’


u’ = cosx – (cosx – x sinx)


u’ = x sinx



Applying Product rule for finding the term xsinx in v’


(gh)′ = g′h + gh′


Taking g = xand h = sinx


[]’ = (1) (sinx) + x (cosx)


[]’ = sinx + x cosx


Applying the above obtained value for finding v’


v’ = sinx + x cosx - sinx


v’ = x cosx


Putting the above obtained values in the formula:-









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