To Find: Differentiation

NOTE : When 2 functions are in the product then we used product rule i.e

Formula used: (cot^a nu) = acot^{a - 1}(nu) (cot nu) (nu) and = nx^{n - 1}

Let us take y = cot²x

So, by using the above formula, we have

cot²x = 2cot(x) = - 2cotx (cosec²x).

Differentiation of y = cot²x is - 2cotx (cosec²x)