In a circle of diameter 30 cm, the length of a chord is 15 cm. Find the length of the minor arc of the chord.

Diameter = 30 cm


Length of chord = 15 cm


Radius = 15 cm [ r = 0.5 x diameter ]


Since the radius is equal to the length of the chord


Hence the formed triangle in the circle is an equilateral triangle.


θ = 60°


We know that l = r × θ


l = = 5 x 3.14 = 15.7


Therefore, the length of the minor arc is 15.7 cm


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