In a circle of diameter 30 cm, the length of a chord is 15 cm. Find the length of the minor arc of the chord.
Diameter = 30 cm
Length of chord = 15 cm
Radius = 15 cm [ r = 0.5 x diameter ]
Since the radius is equal to the length of the chord
Hence the formed triangle in the circle is an equilateral triangle.
θ = 60°
We know that l = r × θ
l = = 5 x 3.14 = 15.7
Therefore, the length of the minor arc is 15.7 cm