To Find: General solution.

Given: 4sin x cos x + 2sin x + 2cos x + 1 = 0 2sin x(2cos x + 1) + 2cos x + 1 = 0

So (2cos x + 1)( 2sin x + 1) = 0

cos x = = cos() or sin x = = sin

Formula used: cos = cos = 2n or sin = sin = m + (-1)^m where n,m I

x = 2n or x = m +(-1)^m . where n, m I

So the general solution is x =2n or x = m +(-1)^m . where n, m I