To Find: General solution.

Given: 2 tan x – cot x + 1 = 0 2tan²x – 1 + tan x = 0 2tan²x – 1 + 2tan x – tanx = 0 2tanx(tanx +1) – (1+ tanx) = 0

(2tanx-1) (1+ tanx) = 0 tan x = = or tan x = -1 = tan

Formula used: tan = tan = n , n I

x = n or x = n

So the general solution is x = nor x = n where n I