Find the equation of the ellipse with eccentricity , foci on the y-axis, center at the origin and passing through the point (6, 4).
Given that
we know that,
We know that,
c2 = a2 – b2
…(i)
It is also given that Coordinates of foci is on the y – axis
So, Equation of ellipse is of the form
Substituting the value of b2 in above eq., we get
…(ii)
Given that ellipse passing through the points (6, 4)
So, point (6, 4) will satisfy the eq. (ii)
Taking point (6, 4) where x = 6 and y = 4
Putting the values in eq. (ii), we get
Substituting the value of a2 in eq. (i), we get
Substituting the value of a2 and b2 in the equation of an ellipse, we get
or 16x2 + 7y2 = 688