Mark the tick against the correct answer in the following:
let Z be the set of all integers and let a * b = a – b + ab. Then, * is
According to the question ,
Q = { All integers }
R = {(a, b) : a * b = a – b + ab }
Formula
* is commutative if a * b = b * a
* is associative if (a * b) * c = a * (b * c)
Check for commutative
Consider , a * b = a – b + ab
And , b * a = b – a + ba
Both equations are not the same and will not always be true .
Therefore , * is not commutative ……. (1)
Check for associative
Consider , (a * b) * c = (a – b + ab) * c
= a – b + ab – c +(a – b + ab)c
=a – b +ab – c +ac – bc + abc
And , a * (b * c) = a * (b – c + bc)
= a - (b – c + bc) + a(b – c + bc)
=a – b + c – bc + ab – ac + abc
Both the equation are not the same and therefore will not always be true.
Therefore , * is not associative ……. (2)
Now , according to the equations (1) , (2)
Correct option will be (C)