Mark the tick against the correct answer in the following:

let Z be the set of all integers and let a * b = a – b + ab. Then, * is


According to the question ,


Q = { All integers }


R = {(a, b) : a * b = a – b + ab }


Formula


* is commutative if a * b = b * a


* is associative if (a * b) * c = a * (b * c)


Check for commutative


Consider , a * b = a – b + ab


And , b * a = b – a + ba


Both equations are not the same and will not always be true .


Therefore , * is not commutative ……. (1)


Check for associative


Consider , (a * b) * c = (a – b + ab) * c


= a – b + ab – c +(a – b + ab)c


=a – b +ab – c +ac – bc + abc


And , a * (b * c) = a * (b – c + bc)


= a - (b – c + bc) + a(b – c + bc)


=a – b + c – bc + ab – ac + abc


Both the equation are not the same and therefore will not always be true.


Therefore , * is not associative ……. (2)


Now , according to the equations (1) , (2)


Correct option will be (C)

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