For all a, b ∈ N, we define a * b = a3 + b3.
Show that * is commutative but not associative.
let a = 1,b = 2N
a*b = 13 + 23 = 9
And b*a = 23 + 13 = 9
Hence * is commutative.
Let c = 3
(a*b)*c = 9*c = 93 + 33
a*(b*c) = a*(23 + 33) = 1*35 = 13 + 353
(a*b)*c a*(b*c)
Hence * is not associative.