For all a, b N, we define a * b = a3 + b3.

Show that * is commutative but not associative.


let a = 1,b = 2N


a*b = 13 + 23 = 9


And b*a = 23 + 13 = 9


Hence * is commutative.


Let c = 3


(a*b)*c = 9*c = 93 + 33


a*(b*c) = a*(23 + 33) = 1*35 = 13 + 353


(a*b)*c a*(b*c)


Hence * is not associative.


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